69. Sqrt(x)

문제

Implement int sqrt(int x).

Compute and return the square root of x, where x is guaranteed to be a non-negative integer.

Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.

Example 1:

Input: 4
Output: 2

Example 2:

Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since 
             the decimal part is truncated, 2 is returned.

풀이

문제의 의도를 여전히 파악못하겠다. 단순히 math.sqrt를 호출하면 되는 것인가?

class Solution:
    def mySqrt(self, x: int) -> int:
        return int(x**(1/2))